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Next: Subcooled boiling model
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Previous: Wall shear stress
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Grid spacer pressure loss modeling
The pressure loss of a spacer is like all other two-phase flow phenomena very
complicated to model. The treatment of a spacer depends on whether the spacer is
of wire-wrapped or grid spacer type. In the subsequent analysis we assume a grid
type spacer.
According to Lahey and Moody the total (integral) pressure loss due to a grid
spacer,
,
can be modeled by the empirical expression
![\begin{displaymath}
\Delta p_{\mbox{\protect\scriptsize spacer}} = K_{\mbox{\pr...
...c{\rho_\ell - \rho_g}{\rho_g} \right]\mbox{$<\!{x}\!>$}\right)
\end{displaymath}](img1256.gif) |
(6.77) |
where
[--] is the single-phase loss coefficient determined by
experiment.
The typical pressure variation caused by the grid spacer is depicted in Figure
6.3. We have to approximate this pressure variation
appropriately in order to solve the conservation equations which describe the
hydraulics of the reactor core. We could, for instance, use the design
approximation shown in the figure with a dashed attribute (-).
However, since it is the differentiated version of the design approximation
which enters the conservation equation in the form of a pressure loss per unit
length,
,
(see (6.57)) this design approximation is
inconvenient in view of obtaining a numerical solution to the problem.
In order to avoid any discontinuities which may cause troubles with the
numerical solution of the conservation equations we will employ a smoothed
version of the design approximation shown in Figure
6.3 instead of using the design approximation directly. The
derivative of this smoothed design approximation is shown in Figure
6.4.
The derivative of this smoothed design approximation,
,
has the
following functional form
 |
(6.78) |
where C is a constant [N/m].
The shape of the design approximation which is schematically illustrated in Figure
6.4 has the following properties
-
is continuous.
-
is continuous.
The width of the pressure pulse,
,
is given by
 |
(6.79) |
The constant C in (6.88) is determined by
 |
(6.80) |
Carrying out the integration reveals that the height of the pressure pulse, C,
is governed by
 |
(6.81) |
Next: Subcooled boiling model
Up: External
Previous: Wall shear stress
  Contents
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